4x^2=1.44

Solution for 4x^2=1.44 equation:

4x^2=1.44

We move all terms to the left:

4x^2-(1.44)=0

We add all the numbers together, and all the variables

4x^2-1.44=0

a = 4; b = 0; c = -1.44;
Δ = b2-4ac
Δ = 02-4·4·(-1.44)
Δ = 23.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{23.04}}{2*4}=\frac{0-\sqrt{23.04}}{8}
=-\frac{\sqrt{}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{23.04}}{2*4}=\frac{0+\sqrt{23.04}}{8}
=\frac{\sqrt{}}{8}
$